Write a Java Program to check Armstrong number.
Answers
Let's try to understand why 153 is an Armstrong number.
153 = (1*1*1)+(5*5*5)+(3*3*3)
where:
(1*1*1)=1
(5*5*5)=125
(3*3*3)=27
So:
1+125+27=153
Let's try to understand why 371 is an Armstrong number.
371 = (3*3*3)+(7*7*7)+(1*1*1)
where:
(3*3*3)=27
(7*7*7)=343
(1*1*1)=1
So:
27+343+1=371
Let's see the java program to check Armstrong Number.
class ArmstrongExample{
public static void main(String[] args) {
int c=0,a,temp;
int n=153;//It is the number to check armstrong
temp=n;
while(n>0)
{
a=n%10;
n=n/10;
c=c+(a*a*a);
}
if(temp==c)
System.out.println("armstrong number");
else
System.out.println("Not armstrong number");
}
}
Output:
armstrong number
ola!!
class ArmstrongExample{
public static void main(String[] args) {
int c= 0,a,temp;
int n= 153;//It is the number to check armstrong
temp=n;
while(n> 0 )
{
a=n% 10;
n=n/ 10;
c=c+(a*a*a);
}
if (temp==c)
System.out.println( "armstrong number" );
else
System.out.println( "Not armstrong number" );
}
}
Output:
armstrong number
tysm❤