Computer Science, asked by Trived, 7 months ago

Write a JAVA program to check if the given number is a Hardy Ramanujan Number. basic way :)

Answers

Answered by Pikachu453
2

Compilation: javac Ramanujan.java

* Execution: java Ramanujan n

*

* Prints out any number between 1 and n that can be expressed as the

* sum of two cubes in two (or more) different ways.

*

* % java Ramanujan 1728

*

* % java Ramanujan 1729

* 1729 = 1^3 + 12^3 = 9^3 + 10^3

*

* % java Ramanujan 10000

* 1729 = 1^3 + 12^3 = 9^3 + 10^3

* 4104 = 2^3 + 16^3 = 9^3 + 15^3

*

* % java Ramanujan 100000

* 1729 = 1^3 + 12^3 = 9^3 + 10^3

* 4104 = 2^3 + 16^3 = 9^3 + 15^3

* 13832 = 2^3 + 24^3 = 18^3 + 20^3

* 39312 = 2^3 + 34^3 = 15^3 + 33^3

* 46683 = 3^3 + 36^3 = 27^3 + 30^3

* 32832 = 4^3 + 32^3 = 18^3 + 30^3

* 40033 = 9^3 + 34^3 = 16^3 + 33^3

* 20683 = 10^3 + 27^3 = 19^3 + 24^3

* 65728 = 12^3 + 40^3 = 31^3 + 33^3

* 64232 = 17^3 + 39^3 = 26^3 + 36^3

*

* % java Ramanujan 100000000 | sort -n // sort results numerically in Unix

* 1729 = 1^3 + 12^3 = 9^3 + 10^3

* ...

* 87539319 = 167^3 + 436^3 = 228^3 + 423^3

* 87539319 = 167^3 + 436^3 = 255^3 + 414^3

* 87539319 = 228^3 + 423^3 = 255^3 + 414^3

* ...

*

* Bugs

* ----

* If a number can be expressed as a sum of cubes in more than two

* different ways, the program prints some duplicates.

*

******************************************************************************/

public class Ramanujan {

public static void main(String[] args) {

// read in one command-line argument

int n = Integer.parseInt(args[0]);

// for each a, b, c, d, check whether a^3 + b^3 = c^3 + d^3

for (int a = 1; a <= n; a++) {

int a3 = a*a*a;

if (a3 > n) break;

// start at a to avoid print out duplicate

for (int b = a; b <= n; b++) {

int b3 = b*b*b;

if (a3 + b3 > n) break;

// start at a + 1 to avoid printing out duplicates

for (int c = a + 1; c <= n; c++) {

int c3 = c*c*c;

if (c3 > a3 + b3) break;

// start at c to avoid printing out duplicates

for (int d = c; d <= n; d++) {

int d3 = d*d*d;

if (c3 + d3 > a3 + b3) break;

if (c3 + d3 == a3 + b3) {

System.out.print((a3+b3) + " = ");

System.out.print(a + "^3 + " + b + "^3 = ");

System.out.print(c + "^3 + " + d + "^3");

System.out.println();

}

}

}

}

}

}

}

Copyright © 2000–2017, Robert Sedgewick and Kevin Wayne.

Last updated: Fri Oct 20 14:12:12 EDT 2017.

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