write a Java program to duplicate an element from a set of elements.Get the array size and elements .Get the position of the element to be replicated at the end of the array.If the position given is greater than the size of an array display the message as "Position is greater than the size of an array".If the size of the array is zero or lesser then display the message "Invalid array size".
Answers
Program:
import java.util.*;
import java.io.*;
public class Main
{
public static void main(String[] args)
{
int n;
Scanner sc=new Scanner(System.in);
n=sc.nextInt(); //array size
if(n<=0){ //if array size is 0 or less
System.out.println("Invalid array size");
System.exit(0);
}
int[] array = new int[n];
for(int i=0; i<n; i++) //taking elements into array
{
array[i]=sc.nextInt();
}
int ind=sc.nextInt(); //taking the index of element to be duplicated and it should be in the range of 0 to n-1
if(ind>=n){ //If index is greater than array size [0..n-1]
System.out.println("Position is greater than the size of an array");
System.exit(0);
}
System.out.println(Arrays.toString(array)); //initial array
array = Arrays.copyOf(array, array.length + 1);
//create new array from old array and allocate one more element
array[array.length - 1] = array[ind];
//adding duplicate of indexed element at the end of array; new array
System.out.println(Arrays.toString(array));
}
}
Test case 1:
5
1
2
3
4
5
2 //element at index 2 is 3. Add duplicate 3 at the end of array
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5, 3]
Test case 2:
-1 //Array size should be greater than zero. Invalid size given.
Invalid array size
Test case 3:
5
1
2
3
4
5
5
//Index starts with 0, ends with n-1 i.e., 4. So, 5 is out of the bound index.
Position is greater than the size of an array
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