Question

Write a Java program to input the dimensions of a rectangle and find the area of
that square whose perimeter is equal to the perimeter of the rectangle.​

Answer 1

Explanation:

public class Rectangle

{

public static void main( )

{

int b, l, ar, asq;

b = 4;

l = 8;

ar = 2( l+b );

asq = ar;

System.out.println (" The area of square =" + asq);

}

}

Answer 2

Question

Write a program to input the dimensions of a rectangle and find the area of that square whose perimeter is equal to the perimeter of the rectangle.

Solution:

import java.util.*;

public class Question

{

static void main()

{

Scanner sc=new Scanner(System.in);

float l,b,p,s,a;

System.out.println("Enter the length & breadth of the rectangle:");

l=sc.nextFloat();

b=sc.nextFloat();

p=2*(l+b); //perimeter of the rectangle

s=p/4; /*side of the square whose perimeter is equal

to the perimeter of the rectangle*/

a=s*s; //area of the square

System.out.println("Area of the Square:"+a);

}

}

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