Computer Science, asked by jrs1970, 7 months ago

write a Java program to input three numbers and store it's result into a variable. Divide the result by the last number and print it's result​

Answers

Answered by urja79
1

Explanation:

There are three ways to reverse a number in Java.

1) Using while loop

2) Using for loop

3) Using recursion

4) Reverse the number without user interaction

Program 1: Reverse a number using while Loop

The program will prompt user to input the number and then it will reverse the same number using while loop.

import java.util.Scanner;

class ReverseNumberWhile

{

public static void main(String args[])

{

int num=0;

int reversenum =0;

System.out.println("Input your number and press enter: ");

//This statement will capture the user input

Scanner in = new Scanner(System.in);

//Captured input would be stored in number num

num = in.nextInt();

//While Loop: Logic to find out the reverse number

while( num != 0 )

{

reversenum = reversenum * 10;

reversenum = reversenum + num%10;

num = num/10;

}

System.out.println("Reverse of input number is: "+reversenum);

}

}

Output:

Input your number and press enter:

145689

Reverse of input number is: 986541

Program 2: Reverse a number using for Loop

import java.util.Scanner;

class ForLoopReverseDemo

{

public static void main(String args[])

{

int num=0;

int reversenum =0;

System.out.println("Input your number and press enter: ");

//This statement will capture the user input

Scanner in = new Scanner(System.in);

//Captured input would be stored in number num

num = in.nextInt();

/* for loop: No initialization part as num is already

* initialized and no increment/decrement part as logic

* num = num/10 already decrements the value of num

*/

for( ;num != 0; )

{

reversenum = reversenum * 10;

reversenum = reversenum + num%10;

num = num/10;

}

System.out.println("Reverse of specified number is: "+reversenum);

}

}

Output:

Input your number and press enter:

56789111

Reverse of specified number is: 11198765

Program 3: Reverse a number using recursion

import java.util.Scanner;

class RecursionReverseDemo

{

//A method for reverse

public static void reverseMethod(int number) {

if (number < 10) {

System.out.println(number);

return;

}

else {

System.out.print(number % 10);

//Method is calling itself: recursion

reverseMethod(number/10);

}

}

public static void main(String args[])

{

int num=0;

System.out.println("Input your number and press enter: ");

Scanner in = new Scanner(System.in);

num = in.nextInt();

System.out.print("Reverse of the input number is:");

reverseMethod(num);

System.out.println();

}

}

Output:

Input your number and press enter:

5678901

Reverse of the input number is:1098765

Example: Reverse an already initialized number

In all the above programs we are prompting user for the input number, however if do not want the user interaction part and want to reverse an initialized number then this is how you can do it.

class ReverseNumberDemo

{

public static void main(String args[])

{

int num=123456789;

int reversenum =0;

while( num != 0 )

{

reversenum = reversenum * 10;

reversenum = reversenum + num%10;

num = num/10;

}

System.out.println("Reverse of specified number is: "+reversenum);

}

}

Output:

Reverse of specified number is: 987654321

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