Question

Write a java program using loop to check whether a number is perfect square or not. ​

Answer 1

Answer:

input:

package com.beginnersbook;

import java.util.Scanner;

class JavaExample {  

   static boolean checkPerfectSquare(double x)  

   {  

// finding the square root of given number  

double sq = Math.sqrt(x);  

/* Math.floor() returns closest integer value, for

 * example Math.floor of 984.1 is 984, so if the value

 * of sq is non integer than the below expression would

 * be non-zero.

 */

return ((sq - Math.floor(sq)) == 0);  

   }  

 

   public static void main(String[] args)  

   {  

System.out.print("Enter any number:");

Scanner scanner = new Scanner(System.in);

double num = scanner.nextDouble();  

scanner.close();

if (checkPerfectSquare(num))  

 System.out.print(num+ " is a perfect square number");  

else

 System.out.print(num+ " is not a perfect square number");  

   }  

}

Answer 2

Answer :-

Java Program to Check if a given Number is Perfect Number

• public class Perfect.

• int n, sum = 0;

• Scanner s = new Scanner(System.

• System. out. print("Enter any integer you want to check:");

• n = s. nextInt();

• for(int i = 1; i < n; i++)

• if(n % i == 0)

• sum = sum + i;