Question

write a linear equation such that the points (- 6,6 )and( 6, - 6) lies on it.​

Answer 1

Answer:

x+y=0

Step-by-step explanation:

$y - y1 = \frac{y2 - y1}{x2 - x1} (x - x1) \\ \\ y - 6= \frac{ - 6 - 6}{6 - ( - 6)} (x - ( - 6)) \\ \\ y - 6= \frac{ - 12}{12} (x + 6) \\ \\ y - 6= - 1(x + 6) \\ \\ y - 6 + x + 6=0 \\ \\ x + y=0$