Question

write a loop that prints out the index of every 'i' in 'mississippi

Answer 1

Program:

#string  

x="mississippi"

#char to match  

char="i"

#count variable

count=0

#using loop to iterate over string

for i in x:

   #if statement to check the condition

   if (i == char):

       #displaying the index of i

       print("index of i is - ", count)

   #incrementing count with 1    

   count=count+1

Output:

index of i is -  1

index of i is -  4

index of i is -  7

index of i is -  10

Explanation:

• string "mississippi" is stored in variable x.
• char variable stores "i".
• Initializing the count variable to 0. The count will store the index of i in the string.
• Using a for loop to iterate over the string x.
• if statement will check whether the i == char.
• the print function is used to display the value of the count variable.
• incrementing the value of the count variable.

Learn More:

• what is indexing: https://brainly.in/question/3356261
• index number: https://brainly.in/question/9130162