Chemistry, asked by Afia18, 11 months ago

write a materials required,aim, procedure, conclusion and observation

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Faiqa93: which activity?
Afia18: both

Answers

Answered by Faiqa93
113

ACTIVITY 1.2

AIM :- To observe a chemical reaction.

MATERIALS REQUIRED :- Two test tubes, lead nitrate, potassium iodide.

PROCEDURE :-

  • Take two test tubes and add lead nitrate and potassium iodide in the test tubes respectively to make a solution.
  • Now, add potassium iodide solution to the lead nitrate solution.
  • Observe the changes occurring.

OBSERVATION :- The solution changes into a bright yellow color.

CONCLUSION :- In a chemical reaction, the solution can change color.


ACTIVITY 1.3

AIM :- To observe a chemical reaction.

MATERIALS REQUIRED :- Zinc granules, conical flask or a test tube, dil. hydrochloric acid or sulphuric acid.

PROCEDURE :-

  • Take a conical flask and put some zinc granules in it.
  • Add dil. hydrochloric acid or sulphuric acid in it.
  • Observe the changes.

OBSERVATION :- The bubbles start coming out and the conical flask or the test tube becomes warm.

CONCLUSION :- The reaction is a single displacement reaction where zinc displaces the hydrogen to form hydrogen gas and the resulting colution is zinc chloride. Zinc reacts quickly with the acid to form bubbles of hydrogen.

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KeerthanaMG: thank you
Faiqa93: Your welcome:)
Answered by SmãrtyMohït
69
❤❤I hope it helps you ✌✌

➡Aim:-
To show change in state and colour when a chemical reaction takes place.

➡Apparatus:-
lead nitrate solution, potassium iodide solution, test tube, and a conical flask.

➡Procedure:-
Take lead nitrate solution in a test tube Add potassium iodide solution to this.

➡Observation:-
lead nitrate reacts with potassium iodide to give lead iodide and potassium nitrate.

The colour of the products is different from that of the reactants.

➡Conclusion:-
Pb(NO3)2 + 2KI → PbI2 + 2KNO3. 

The change in colour is because lead iodide and potassium nitrate have been formed after the reaction. PbI2 is a yellow ppt. KNO3 is a colourless solution.

☆☆here is your another answer :-

➡Aim:-
To show the interaction between zinc granules and hydrochloric acid or sulphuric acidformation of H gas)

➡Apparatus:-
Zinc granules, conical flask, test tube, hydrochloric acid / sulphuric acid

➡Procedure:-
Take a few zinc granules in a conical flask or a test tube. Add dilute hydrochloric acid or sulphuric acid to this.

Touch the conical flask or test tube.

➡Observation: -
A gas is evolved and the conical flask is warm 

➡Conclusion:-
From this we conclude that when a chemical reaction takes place there is a change in the state, colour, and temperature.

Zn + 2HCl → ZnCl2 + H2↑ + heat .

Zn + H2SO4 → ZnSO4 + H2↑ + heat.

✌✌happy to help u✌✌

KeerthanaMG: thank you for the answer.. it helped a lot.
27jenny: wow!!!! nice answer
IshikaSinha: that's very helpful
DeeptiMohanty: ooo mera intelligent bhai ....✌^_^
DeeptiMohanty: gr8 answer ....✨✨
adithyashasan007: nice.. helpful answer.. :-)
adithyashasan007: :-)
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