Question

Write a menu daiven program to convert decimal
number to binary and binary number to decimal based
on user choice.​

Answer 1

Program to convert binary to decimal

#include <math.h>

#include <stdio.h>

int convert(long long n);

int main() {

long long n;

printf("Enter a binary number: ");

scanf("%lld", &n);

printf("%lld in binary = %d in decimal", n, convert(n));

return 0;

}

int convert(long long n) {

int dec = 0, i = 0, rem;

while (n != 0) {

rem = n % 10;

n /= 10;

dec += rem * pow(2, i);

++i;

}

return dec;

}

Output

Enter a binary number: 110110111

110110111 in binary = 439

Program to convert decimal to binary

#include <math.h>

#include <stdio.h>

long long convert(int n);

int main() {

int n;

printf("Enter a decimal number: ");

scanf("%d", &n);

printf("%d in decimal = %lld in binary", n, convert(n));

return 0;

}

long long convert(int n) {

long long bin = 0;

int rem, i = 1, step = 1;

while (n != 0) {

rem = n % 2;

printf("Step %d: %d/2, Remainder = %d, Quotient = %d\n", step++, n, rem, n / 2);

n /= 2;

bin += rem * i;

i *= 10;

}

return bin;

}

Output

Enter a decimal number: 19

Step 1: 19/2, Remainder = 1, Quotient = 9

Step 2: 9/2, Remainder = 1, Quotient = 4

Step 3: 4/2, Remainder = 0, Quotient = 2

Step 4: 2/2, Remainder = 0, Quotient = 1

Step 5: 1/2, Remainder = 1, Quotient = 0

19 in decimal = 10011 in binary

$bts (◍•ᴗ•◍)❤ exo$

Answer 2

Answer:

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