Question

Write a menu-driven program in Java to accept a number from the user and check whether it is Palindrome number or not?​

Answer 1

ANSWER

import java.util.Scanner; public class KboatPalinOrPerfect { public static void main(String args[]) { Scanner in = new Scanner(System.in); System.out.println("1. Palindrome number"); System.out.println("2. Perfect number"); System.out.print("Enter your choice: "); int choice = in.nextInt(); System.out.print("Enter number: "); int num = in.nextInt(); switch (choice) { case 1: int copyNum = num; int revNum = 0; while(copyNum != 0) { int digit = copyNum % 10; copyNum /= 10; revNum = revNum * 10 + digit; } if (revNum == num) System.out.println(num + " is palindrome"); else System.out.println(num + " is not palindrome"); break; case 2: int sum = 0; for (int i = 1; i <= num / 2; i++) { if (num % i == 0) { sum += i; } } if (num == sum) System.out.println(num + " is a perfect number"); else System.out.println(num + " is not a perfect number"); break; default: System.out.println("Incorrect Choice"); break; } } }