Question

Write a menu driven program to accept a decimal number or a number in its binary form and convert it into the other form based on the user's choice. Use switch and write an error message for a wrong choice.
Sample input and output:
1 Convert to binary
2 Convert to decimal
Enter choice:1
Enter number in decimal form:9
In binary form:1001
Please help me solve this problem....its Java loops.

Answer 1

Given a decimal number as input, we need to write a program to convert the given decimal number into equivalent binary number.

Examples:

Input : 7 Output : 111 Input : 10 Output : 1010 Input: 33 Output: 10000

Algorithm:



Store the remainder when the number is divided by 2 in an array.

Divide the number by 2

Repeat the above two steps until the number is greater than zero.

Print the array in reverse order now.

For Example:
If the binary number is 10.
Step 1: Remainder when 10 is divided by 2 is zero. Therefore, arr[0] = 0.
Step 2: Divide 10 by 2. New number is 10/2 = 5.
Step 3: Remainder when 5 is divided by 2 is 1. Therefore, arr[1] = 1.
Step 4: Divide 5 by 2. New number is 5/2 = 2.
Step 5: Remainder when 2 is divided by 2 is zero. Therefore, arr[2] = 0.
Step 6: Divide 2 by 2. New number is 2/2 = 1.
Step 7: Remainder when 1 is divided by 2 is 1. Therefore, arr[3] = 1.
Step 8: Divide 1 by 2. New number is 1/2 = 0.
Step 9: Since number becomes = 0. Print the array in reverse order. Therefore the equivalent binary number is 1010.

Below diagram shows an example of converting the decimal number 17 to equivalent binary number.