Question

Write a menu driven program to accept a word from the user and display the following

patterns as per the user’s choice:

If choice is “rectangle” - @ @ @ @ @

@ @ @ @ @

@ @ @ @ @
If choice is “triangle” - V I K A A S A

V I K A A S

V I K A A

V I K A

V I K

V I

V​

Answer 1

Answer:

Write a menu driven program to accept a word from the user and display the following

patterns as per the user’s choice:

If choice is “rectangle” - @ @ @ @ @

@ @ @ @ @

@ @ @ @ @

If choice is “triangle” - V I K A A S A

V I K A A S

V I K A A

V I K A

V I K

V I

V​

Explanation:

Answer 2

Explanation:

Code:-

import java.util.Scanner;

public class Menu

{

public static void main(String[] args)

{

int choice;

double area;

int l,b;

int a;

int r;

Scanner sc = new Scanner(System.in);

System.out.println("1- Area of Right Triangle");

System.out.println("2- Area of Equilateral Triangle");

System.out.println("3- Area of Square");

System.out.println("4- Area of Rectangle");

System.out.println("5- Area of Circle");

System.out.println("------------------------------");

System.out.print("Select your choice=");

choice = sc.nextInt();

switch (choice)

{

case 1:

System.out.print("Enter l=");

l=sc.nextInt();

System.out.print("Enter b=");

b=sc.nextInt();

area=(l*b)/2;

System.out.println("Area of Right Triangle="+area);

break;

case 2:

System.out.print("Enter a=");

a=sc.nextInt();

area=(a*a*Math.sqrt(3))/4;

System.out.println("Area of Equilateral Triangle="+area);

break;

case 3:

System.out.print("Enter a=");

a=sc.nextInt();

area=a*a;

System.out.println("Area of Square="+area);

break;

case 4:

System.out.print("Enter l=");

l=sc.nextInt();

System.out.print("Enter b=");

b=sc.nextInt();

area=l*b;

System.out.println("Area of Rectangle="+area);

break;

case 5:

System.out.print("Enter r=");

r=sc.nextInt();

area=r*r*22/7;

System.out.println("Area of Circle="+area);

break;

default:

System.out.print("Enter valid month.");

}

}

}

Output

Attached above