write a note on the assignment of atoms per unit cell in fcc
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Explanation:
The total number of atoms per unit cell in bcc.
=Nc8+Nb1=88+11=1+1=2=Nc8+Nb1=88+11=1+1=2
Nb=Nb= Number of atoms inside the body , NcNc is the number of atoms at the corners.
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Explanation:
In a FCC lattice there rer 8 atoms at eight corners and 6 at face centers,
Now each corner contributes to eight cells so per unit cell contribution is 81×8=1atom.
Now similarly each face center contributes to two unit cells so contribution per unit cell by six face centers is equal to 21×6=3 atoms. Hence total no. of atoms per unit cell of FCC lattice is (1+3)=4 atoms.
For BCC-
A bcc has one atom in center and 81th part of 8 corner atoms i.e 1 atom.
In total there are 1+1=2 atoms.
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