Question

write a number which less than half of 100, greater that 40,tens digit is 2 greater than the units digit, sum of digit in 6.​

Answer 1

42 is the correct answer.

Answer 2

Given :-

• Number is less than half of 100 .
• Greater than 40 .
• Tens digit is 2 greater than the unit's digit .
• Sum of digits is 6.

Solution :-

Let us assume that, the required number is (10x + y) .

→ Less than = 100/2 = Less than 50 and greater than 40 .

so,

→ 40 < 10x + y < 50 .

now,

→ x + y = 6

→ x - y = 2

2x = 8

→ x = 4 .

then,

→ y = 6 - 4 = 2 .

therefore,

→ Required number = 10x + y = 10*4 + 2 = 40 + 2 = 42 (Ans.)