Question

write a pair of fraction whose sum is 7/11 and defference is 2/11​

Answer 1

Answer:

VERIFIED ANSWER ‼️

Let the fractions be a/b and x/y

Let the fractions be a/b and x/yAccording to question

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)On adding equation 1 and 2, we get

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)On adding equation 1 and 2, we get2× a/b = ( 7 + 2) / 11

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)On adding equation 1 and 2, we get2× a/b = ( 7 + 2) / 11=> a/b = 9 / 22

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)On adding equation 1 and 2, we get2× a/b = ( 7 + 2) / 11=> a/b = 9 / 22Now,

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)On adding equation 1 and 2, we get2× a/b = ( 7 + 2) / 11=> a/b = 9 / 22Now,On substituting the value of a/b in equation 1, we get

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)On adding equation 1 and 2, we get2× a/b = ( 7 + 2) / 11=> a/b = 9 / 22Now,On substituting the value of a/b in equation 1, we get9 / 22 + x/y = 7 / 11

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)On adding equation 1 and 2, we get2× a/b = ( 7 + 2) / 11=> a/b = 9 / 22Now,On substituting the value of a/b in equation 1, we get9 / 22 + x/y = 7 / 11=> x/y = 7 / 11 - 9 / 22

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)On adding equation 1 and 2, we get2× a/b = ( 7 + 2) / 11=> a/b = 9 / 22Now,On substituting the value of a/b in equation 1, we get9 / 22 + x/y = 7 / 11=> x/y = 7 / 11 - 9 / 22=> x/y = ( 14 - 9) / 22

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)On adding equation 1 and 2, we get2× a/b = ( 7 + 2) / 11=> a/b = 9 / 22Now,On substituting the value of a/b in equation 1, we get9 / 22 + x/y = 7 / 11=> x/y = 7 / 11 - 9 / 22=> x/y = ( 14 - 9) / 22=> x/y = 5 / 22

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)On adding equation 1 and 2, we get2× a/b = ( 7 + 2) / 11=> a/b = 9 / 22Now,On substituting the value of a/b in equation 1, we get9 / 22 + x/y = 7 / 11=> x/y = 7 / 11 - 9 / 22=> x/y = ( 14 - 9) / 22=> x/y = 5 / 22First fraction = 9 / 22

Let the fractions be a/b and x/yAccording to questiona/b + x/y = 7 / 11 ------(1)a/b - x/y = 2 / 11 -------(2)On adding equation 1 and 2, we get2× a/b = ( 7 + 2) / 11=> a/b = 9 / 22Now,On substituting the value of a/b in equation 1, we get9 / 22 + x/y = 7 / 11=> x/y = 7 / 11 - 9 / 22=> x/y = ( 14 - 9) / 22=> x/y = 5 / 22First fraction = 9 / 22Second fraction = 5 / 22