Question

write a pair of fraction whose sum is 7 upon 11 and difference is 2 upon 11

Answer 1

Let the fractions be a/b and x/y

According to question

a/b + x/y = 7 / 11 ------(1)

a/b - x/y = 2 / 11 -------(2)

On adding equation 1 and 2, we get


2× a/b = ( 7 + 2) / 11

=> a/b = 9 / 22

Now,

On putting the value of a/b in equation 1, we get

9 / 22 + x/y = 7 / 11

=> x/y = 7 / 11 - 9 / 22

=> x/y = ( 14 - 9) / 22

=> x/y = 5 / 22

First fraction = 9 / 22

Second fraction = 5 / 22

Answer 2

Step-by-step explanation:

find the difference 5 upon 11 - 7 upon 22