Question

write a pair of fractions whose sum is 7/11 and the difference is 2/11​

Answer 1

Answer:

Step-by-step explanation:

The pair of fractions whose sum is 7/11 and the difference is 2/11 are 5/22 and 9/22 respectively

let x and y be a pair of fraction

Then given that x+ y = 7/11

x= $\frac{7}{11} -y$

Given x-y = 2/11

Substitute x as $\frac{7}{11} -y$

That is $(\frac{7}{11} -y)-y=\frac{2}{11}$

$\frac{7}{11} -2y =\frac{2}{11} \\\\2y = \frac{7}{11} -\frac{2}{11} \\\\2y= \frac{5}{11} \\\\y=\frac{5}{11*2} \\\\y=\frac{5}{22}$

So y= 5/22

x= $\frac{7}{11} -y\\=\frac{7}{11} -\frac{5}{22} \\\\=\frac{1}{11} (7-\frac{5}{2} )\\\\= \frac{1}{11} (\frac{14-5}{2} )\\\\= \frac{1}{11}*\frac{9}{2} \\\\=\frac{9}{22}$

So the pair of fractions are 5/22 and 9/22

Answer 2

Answer:

Answer in attachement

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