Question

write a pair of integer whose product is -39 and whose difference is 16​

Answer 1

Answer:

13 and -3 or. 3 and -13

Step-by-step explanation:

these both pair has difference of 16 and product is -39

Answer 2

Step-by-step explanation:

Given data :

The product of two integers is -39

Difference of the two integers is 16 .

Let the two numbers be x and y.

Forming equations :

$x - y \: = 16 \\ and \: xy = - 39 \\ y = - \frac{39}{x}$

Now, putting the value of y in the first equation, we get :

$x - ( \frac{ - 39}{x} ) = x + \frac{39}{x} = 16$

${x }^{2} + 39 = 16x \\ {x}^{2} - 16x \ + 39 = 0 \\ {x}^{2} - 13x - 3x + 39 = 0 \\ x(x - 13) - 3(x - 13) = 0 \\ (x - 3)(x - 13) = 0 \\ x = 3 \: or \: 13$

When x is 3 , then y = -13

And when x = 13 , then y = -3

Hence, the two numbers are 3 and -13. or -3 and 13 .

# SPJ3