write a pair of integers whose product is -36 and whose difference is 15
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Answered by
1
Step-by-step explanation:
let the 2 no. be x and y
such that x*y= -36 and x-y = 15
x= 15+y........(1)
substitute (1) in x*y
(15+y)y=-36
15y+y² = -36
y²+15y+36 = 0
y²+12y+3y+36=0
y(y+12)+3(y+12)=0
(y+3)(y+12)=0
y=-3 y=-12
x = 15+(-3) x = 15+(-12)
x = 15-3 x = 15-12
x = 18 x = 3
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