Question

Write a pair of integers whose product is – 36 and whose sum is 9.

Answer 1

Hi friend!!

Let the pair is integers be x and y

Given,

Their product is -36 and their sum is 9

→x+y=9

y=9-x

And xy=-36

x(9-x)=-36

9x-x²=-36

x²-9x-36=0

x²-12x+3x-36=0

x(x-12)+3(x-12)=0

(x+3)(x-12)=0

x=12,-3

If x=12; y=9-x=9-12=-3

If x=-3; y=9-x=9+3=12


So the required pair is integers is -3,12

I hope this will help you ;)

Answer 2

Let two numbers be x and y.

Given,

xy=-36.....(i)

x + y = 9 ....(ii)

y= 9-x....(iii)

Substitute value of (iii) in ( i)

x (9-x)= -36.

x^2-9x-36 =0.

x^2-12x+3x-36

x(x-12)+3(x-12)

(x-12) (x+3)

x=12,x= -3.

 Now substitute value of x=12 in (iii)

y=9-12

y=-3.

Substitute value of x= -3 in (iii)

y=9-(-3)

y=12.

Hence, the two numbers can be 12 and -3.

Hope it helps u...
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