Math, asked by bhadrashankar2219, 5 days ago

Write a pair of integers, whose product is–48 and whose difference is 14.

Answers

Answered by sucidsquad01
0

Answer:

let one integer be x

and ather integer be y

Step-by-step explanation:

by ist condition

x + y = -48_____i

by wnd condition

x-y = 14______ii

equation ii can be written as

x-y = 14

x = 14 + y______iii

put the value of x in equation i

14+y+y= -48

2y= -48-14

2y = -62

y = -62/2

y= -31

put the value of y in equation iii

x= 14+(-31)

x= 14-13

x=1

therefore the pair of integers is 1and -31

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