Write a pair of integers whose sum is zero (0) but difference is 12.
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Let the two integer's be 'x' and 'y'.
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x + y = 0 --------(1)
x - y = 12 -------(2)
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Now , Add eq. (1) and eq. (2)
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x + y =0
x - y = 12
_______
2x = 12
_______
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Therefore , x = 6.
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putting the value of 'x' in eq (1) , we get
6+y = 0
y = -6
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THEREFORE , THE PAIR OF INTEGERS ARE (6 , -6).
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