write a pair of interferes whose sum is zero but difference is 12
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Let the two integers be x and y
x+y = 0 ----(1)
x-y = 12 -----(2)
(1) + (2)
x+y = 0
x-y = 12
______
2x = 12
x = 6
x+y = 0
6+y = 0
y = -6
Therefore,the pair of integers is (6,-6)
Answered by
1
x+y = 0
x-y=12
x= 6
and y = (-6)
hence number will
6 and -6
x-y=12
x= 6
and y = (-6)
hence number will
6 and -6
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