Question

write a pair of linear equation which has the unique solution x= -1 and y= -3 . how much such pair can you write
​

Answer 1

Answer:

Infinite

Step-by-step explanation:

a1/a2 ≠ b1/b2

Let the equations be,

a1x + b1y + c1 = 0 a2x + b2y + c2 = 0

Since, x = – 1 and y = 3 is the unique solution of these two equations, then It must satisfy the equations – a1(-1) + b1(3) + c1 = 0 – a1 + 3b1 + c1 = 0 …

(i) and a2(- 1) + b2(3) + c2 = 0 – a2 + 3b2 + c2 = 0

(ii) Since for the different values of a1, b1, c1 and a2, b2, c2 satisfy the Eqs. (i) and (ii).

Thus infinite pair we can write

$hope \: \: it \: helps \: \: you$

❥♥╣XxNashedixX╠♥