Write a pair of negative integers whose sum is - 8 and product is 12.
Answers
Answered by
0
Answer:
-4,-3
Step-by-step explanation:
sum
-4+(-3)=-8
product
(-4)×(-3)=12
Answered by
0
Answer:
let the pair of negative integers are -x , -y
-x-y= -8 , x.y=12
=> -(x+y)= -8
=> x+y=8
(x+y)^2=8^2=64
(x-y)^2+4xy=64
=> (x-y)^2+4.12=64
=> (x-y)^2=64-48
=> (x-y)^2=16
=> (x-y)=+4 , -4
x+y=8
x-y=4
adding,
2x=12
x=12/2
=> x=6
y=8-6=2
again,
x+y=8
x-y= -4
adding ,
2x=4
x=4/2=2
y=8-2=6
so the numbers are -6 and -2
Similar questions