Math, asked by 0585, 2 months ago

Write a pair of negative integers whose sum is - 8 and product is 12.​

Answers

Answered by badboy9824
0

Answer:

-4,-3

Step-by-step explanation:

sum

-4+(-3)=-8

product

(-4)×(-3)=12

Answered by bagkakali
0

Answer:

let the pair of negative integers are -x , -y

-x-y= -8 , x.y=12

=> -(x+y)= -8

=> x+y=8

(x+y)^2=8^2=64

(x-y)^2+4xy=64

=> (x-y)^2+4.12=64

=> (x-y)^2=64-48

=> (x-y)^2=16

=> (x-y)=+4 , -4

x+y=8

x-y=4

adding,

2x=12

x=12/2

=> x=6

y=8-6=2

again,

x+y=8

x-y= -4

adding ,

2x=4

x=4/2=2

y=8-2=6

so the numbers are -6 and -2

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