Question

write a pair of positive integers whose difference is 20 and sum is 40 ​

Answer 1

Step-by-step explanation:

let the integers (positive ) be x and y

case 1

x-y = 20

case 2

x+y = 40

adding case 1 and 2

we get - 2x = 60

x = 30

and substituting in case 1 of value of x

we get

30 -y = 20

y = 30-20

y = 10

.......

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