Question

Write a pair of the integers whose product is _36 and whose difference is 15

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Answer 1

Answer:

Step-by-step explanation:

Let the integers be x and y

Given xy = -36

⇒y= -36/x

Also, x-y = 15

⇒x -(-36/x) = 15

⇒x + 36/x = 15

⇒$x^{2}$ +36= 15$x$

⇒$x^{2} -15x+36=0$

⇒$x^{2} -12x -3x +36=0$

⇒x(x-12) -3 (x-12) = 0

⇒(x-3)(x-12)=0

⇒x = 3 or 12

When x=3, y = -36/3= -12

When x=12, y=-36/12= -3

∴The pair of numbers are (3and -12) & (12 and -3)

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Answer 2

Answer:

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