write a pathagorean triplet whose smallest Member is :-(1)6?
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( 6,8,10 ) is the required Pythagorean triplet .
(6)^2 + (8)^2 = (10)^2
36 + 64 = 100
100
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@Riyaharyanvi..
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( 6,8,10 ) is the required Pythagorean triplet .
(6)^2 + (8)^2 = (10)^2
36 + 64 = 100
100
HOPE IT HELPS YOU !!!!!!........✌️✌️✌️✌️
@Riyaharyanvi..
Answered by
2
General form of triplet are 2m, m² - 1 and m² + 1 (m > 1)
Let 2m = 6
m = 6/2 = 3
Now,
2m = 2 × 3 = 6
m² - 1 = 3² - 1 = 9 - 1 = 8
m² + 1 = 3² + 1 = 9 + 1 = 10
•°• Triplet are 6 , 8 and 10.
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