Write a polynomial that represent the product of 3 consecutive odd integers the first one being 2x-1
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Here, if we take a closer look, putting any integral value of x, we will always get an odd number as multiplying by 2 will give an even number and then subtracting 1 will give on odd number.
The first odd number is : 2x - 1.
Consecutive odd numbers differ by 2.
For example, 3, 5, 7.
So, the second consecutive odd number is : 2x + 1 and 2x + 3
. ° . The required polynomial is
(2x - 1) (2x + 1) (2x + 3)
= (4x² - 1) (2x + 3)
= 8x³ + 12x² - 2x - 3
Hope you understand.
The first odd number is : 2x - 1.
Consecutive odd numbers differ by 2.
For example, 3, 5, 7.
So, the second consecutive odd number is : 2x + 1 and 2x + 3
. ° . The required polynomial is
(2x - 1) (2x + 1) (2x + 3)
= (4x² - 1) (2x + 3)
= 8x³ + 12x² - 2x - 3
Hope you understand.
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