Question

Write a polynomial that represents the product of three consecutive odd integers, the first being (2x-1)
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Answer 1

$\fbox\pink{A}\fbox\green{N}\fbox\pink{S}\fbox\green{W}\fbox\pink{E}\fbox\green{R}\pink{࿐}$

ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ-:

Odd Integers have a difference of $\tt{2}$ between them .

For example, $\tt{3,5,7,9,}$ etc

Now, $\tt{(2x-1)}$is the first of three consecutive integers, so to find other two, just keep adding $\tt{2}$

The next two integers are $\tt{(2x+1)~and~(2x+3)}$ 

Thus we have Three consecutive Odd Integers as $\tt{(2x-1), (2x+1),(2x+3)}$.

Now we just find their product:

$\pink\longrightarrow$$\tt{(2x-1)~(2x+1)~(2x+3)}$

$\green\longrightarrow$ $\tt{(4x^2-1) (2x+3)}$

$\pink\longrightarrow$$\tt{8x^3+12x^2-2x-3}$

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