Question

write a polynomial that represents the product of three consecutive odd integers the first one beings (2x - 1)

Answer 1

Hi Friend !!!


Here is ur answer...,,,,


Let the odd numbers be 2x-1 , 2x+1 , 2x+ 3

THEIR PRODUCT ;

(2x-1)(2x+1)(2x+3)


= (2x)²-1²(2x+3)

= 4x²-1(2x+3)

= 4x²(2x) +3(4x²)-2x-3

= 8x³ + 12x² -2x-3


Hope it helps u : )

Answer 2

Hey There!!

Odd Integers have a difference of 2 between them .


For example, 3,5,7,9, etc


Now, (2x-1) is the first of three consecutive integers, so to find other two, just keep adding 2.

The next two integers are (2x+1) and (2x+3) 


Thus we have Three consecutive Odd Integers as (2x-1), (2x+1), (2x+3) .



Now we just find their product

$(2x-1)(2x+1)(2x+3) \\ \\ = (4x^2-1)(2x+3) \\ \\ = \boxed{8x^3+12x^2-2x-3}$


Hoe it helps
Purva
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