Write a polynomial whose zeroes are 1/2, 1 *
Answers
Answered by
2
f(x) = x³ - 2x² - x + 2 whose zeroes are 1 , 2 & - 1
Step-by-step explanation:
polynomial in x whose zeroes are 1,2 and-1
f(x) = (x - 1)(x - 2)(x -(-1))
=> f(x) = (x - 1)(x - 2)(x + 1)
=> f(x) = (x - 2)(x² - 1)
=> f(x) = x³ - x - 2x² + 2
=> f(x) = x³ - 2x² - x + 2
Verification :
f(1) = 1³ - 2*1² - 1 + 2 = 0
f(2) = 2³ - 2*2² - 2+ 2 = 0
f(-1) = (-1)³ - 2*(-1)² - (-1) + 2 = 0
Step-by-step explanation:
polynomial in x whose zeroes are 1,2 and-1
f(x) = (x - 1)(x - 2)(x -(-1))
=> f(x) = (x - 1)(x - 2)(x + 1)
=> f(x) = (x - 2)(x² - 1)
=> f(x) = x³ - x - 2x² + 2
=> f(x) = x³ - 2x² - x + 2
Verification :
f(1) = 1³ - 2*1² - 1 + 2 = 0
f(2) = 2³ - 2*2² - 2+ 2 = 0
f(-1) = (-1)³ - 2*(-1)² - (-1) + 2 = 0
Answered by
2
f(x) = x³ - 2x² - x + 2 whose zeroes are 1 , 2 & - 1
Step-by-step explanation:
polynomial in x whose zeroes are 1,2 and-1
f(x) = (x - 1)(x - 2)(x -(-1))
=> f(x) = (x - 1)(x - 2)(x + 1)
=> f(x) = (x - 2)(x² - 1)
=> f(x) = x³ - x - 2x² + 2
=> f(x) = x³ - 2x² - x + 2
Verification :
f(1) = 1³ - 2*1² - 1 + 2 = 0
f(2) = 2³ - 2*2² - 2+ 2 = 0
f(-1) = (-1)³ - 2*(-1)² - (-1) + 2 = 0
HOPE SO IT IS HELPFUL..✌️❣️..
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