Math, asked by yachamharshilgupta2, 11 months ago

Write a polynomial whose zeroes are 1/2, 1 *

Answers

Answered by Anonymous

f(x) = x³ - 2x² - x + 2 whose zeroes are 1 , 2 & - 1
Step-by-step explanation:

polynomial in x whose zeroes are 1,2 and-1

f(x) = (x - 1)(x - 2)(x -(-1))

=> f(x) = (x - 1)(x - 2)(x + 1)

=> f(x) = (x - 2)(x² - 1)

=> f(x) = x³ - x - 2x² + 2

=> f(x) = x³ - 2x² - x + 2

Verification :

f(1) = 1³ - 2*1² - 1 + 2 = 0

f(2) = 2³ - 2*2² - 2+ 2 = 0

f(-1) = (-1)³ - 2*(-1)² - (-1) + 2 = 0

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Answered by Dɪʏᴀ4Rᴀᴋʜɪ

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$\huge\red\star\blue{ANSWER}$

f(x) = x³ - 2x² - x + 2 whose zeroes are 1 , 2 & - 1

Step-by-step explanation:

polynomial in x whose zeroes are 1,2 and-1

f(x) = (x - 1)(x - 2)(x -(-1))

=> f(x) = (x - 1)(x - 2)(x + 1)

=> f(x) = (x - 2)(x² - 1)

=> f(x) = x³ - x - 2x² + 2

=> f(x) = x³ - 2x² - x + 2

Verification :

f(1) = 1³ - 2*1² - 1 + 2 = 0

f(2) = 2³ - 2*2² - 2+ 2 = 0

f(-1) = (-1)³ - 2*(-1)² - (-1) + 2 = 0

HOPE SO IT IS HELPFUL..✌️❣️..

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