Question

write a polynomial whose zeroes are (6- root5) and (6+ root5) . Step by Step explanation. ​

Answer 1

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Answer 2

Answer:

gives:

zero 1= (6+$\sqrt5$)

Zero 2=(6-$\sqrt5$)

now, zero 1 +zero 2=6+$\sqrt5$+6-$\sqrt5$

=6+6

=12

also, zero1 *zero2 =(6+$\sqrt5$)*(6-$\sqrt5$)

=$6^{2}-\sqrt5^{2}$

=36-5

=31

Now, we know that, any quadratic polynomial can be expressed in the given form:

x^2+(zero1 +zero 2)x+(zero 1*zero 2)

Putting the obtained values,

$x^2+12x+31$ is the required polynomial