World Languages, asked by rgnag05, 11 months ago

Write a program for inserting(always at end) an element into single linked list
and also perform searching of an element.
Commands to be given from keyboard. 'i' for insert and 's' for search followd by
element for the respective command request. Operations to be performed until
EOF.
EOF on UNIX/Linux is given by hitting Ctrl+d and on windows/dos by hitting
Ctrl+z.
Input format
Refer Sample Input
Output format
Refer Sample Output
Sample testcases
Input 1
Output 1
i 12
i 10
thand
not found
found
s 12
$ 5
i s
55​

Answers

Answered by Aishwarya98
0

/ A complete working C++ program to demonstrate  

//  all insertion methods on Linked List  

#include <bits/stdc++.h>  

using namespace std;  

 

// A linked list node  

class Node  

{  

   public:  

   int data;  

   Node *next;  

};  

 

/* Given a reference (pointer to pointer)  

to the head of a list and an int, inserts  

a new node on the front of the list. */

void push(Node** head_ref, int new_data)  

{  

   /* 1. allocate node */

   Node* new_node = new Node();  

 

   /* 2. put in the data */

   new_node->data = new_data;  

 

   /* 3. Make next of new node as head */

   new_node->next = (*head_ref);  

 

   /* 4. move the head to point to the new node */

   (*head_ref) = new_node;  

}  

 

/* Given a node prev_node, insert a new node after the given  

prev_node */

void insertAfter(Node* prev_node, int new_data)  

{  

   /*1. check if the given prev_node is NULL */

   if (prev_node == NULL)  

   {  

       cout<<"the given previous node cannot be NULL";  

       return;  

   }  

 

   /* 2. allocate new node */

   Node* new_node = new Node();  

 

   /* 3. put in the data */

   new_node->data = new_data;  

 

   /* 4. Make next of new node as next of prev_node */

   new_node->next = prev_node->next;  

 

   /* 5. move the next of prev_node as new_node */

   prev_node->next = new_node;  

}  

 

/* Given a reference (pointer to pointer) to the head  

of a list and an int, appends a new node at the end */

void append(Node** head_ref, int new_data)  

{  

   /* 1. allocate node */

   Node* new_node = new Node();  

 

   Node *last = *head_ref; /* used in step 5*/

 

   /* 2. put in the data */

   new_node->data = new_data;  

 

   /* 3. This new node is going to be  

   the last node, so make next of  

   it as NULL*/

   new_node->next = NULL;  

 

   /* 4. If the Linked List is empty,  

   then make the new node as head */

   if (*head_ref == NULL)  

   {  

       *head_ref = new_node;  

       return;  

   }  

 

   /* 5. Else traverse till the last node */

   while (last->next != NULL)  

       last = last->next;  

 

   /* 6. Change the next of last node */

   last->next = new_node;  

   return;  

}  

 

// This function prints contents of  

// linked list starting from head  

void printList(Node *node)  

{  

   while (node != NULL)  

   {  

       cout<<" "<<node->data;  

       node = node->next;  

   }  

}  

 

/* Driver code*/

int main()  

{  

   /* Start with the empty list */

   Node* head = NULL;  

     

   // Insert 6. So linked list becomes 6->NULL  

   append(&head, 6);  

     

   // Insert 7 at the beginning.  

   // So linked list becomes 7->6->NULL  

   push(&head, 7);  

     

   // Insert 1 at the beginning.  

   // So linked list becomes 1->7->6->NULL  

   push(&head, 1);  

     

   // Insert 4 at the end. So  

   // linked list becomes 1->7->6->4->NULL  

   append(&head, 4);  

     

   // Insert 8, after 7. So linked  

   // list becomes 1->7->8->6->4->NULL  

   insertAfter(head->next, 8);  

     

   cout<<"Created Linked list is: ";  

   printList(head);  

     

   return 0;  

}

Answered by Anonymous
1

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Explanation:

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