Write a program in BASIC 256 to find the squares of numbers less than
1000.
Answers
Answered by
7
⇒ as I had never heard of Basic-256 before. So, I just downloaded it and what I wrote for square root of a number is my second program. In other words, this program works, but I am a novice and specifically disclaim any expertise in this particular variant of BASIC.
- Print "Give me a positive number"
- Input x
- Dim a(100)
- a[0]=x
- for n=1 to 10
- a[n]=.5*(a[n-1]+x/a[n-1])
- print n; " "; a[n]
- next n
Answered by
1
Language:
BASIC-256
Program:
for a= 1 to 999
print a^2
next a
Output:
1.0
4.0
9.0
16.0
25.0
.
.
.
998001.0
Explanation:
- Line 1: Runs a loop from 1 to 999.
- Line 2: returns the squared value.
Attachments:
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