Question

Write a program in c to accept a number and display the digits in words

Answer 1

Program to print number in words
Update: As observed by one of our readers, the above programs fails to show correct output for any integer that ends with 0. Such as 1000, 1090, 10 etc. Therefore I have made little changes in the above program to remove the bug. I have also commented the program well enough so that it could be easy to get the logic.
Program to display number in words
Output
Enter any number to print in words: 1007
One Zero Zero Seven
Happy coding
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<pre><code> ----Your Source Code---- </code></pre>  
/ **
* C program to print number in words
* /
# include < stdio . h >
int main( )
{
int n , num = 0 ;
/ * Input number from user * /
printf( " Enter any number to print
scanf( " % d " , & n ) ;
/ * Store reverse of n in num * /
while( n != 0 )
{
num = ( num * 10 ) + ( n % 10 ) ;
n / = 10 ;
}
/ *
* Extract last digit of number an
* till num becomes 0
* /
while( num != 0 )
{
switch ( num % 10 )
{
case 0 :
printf ( " Zero " ) ;
break ;
case 1 :
printf ( " One " ) ;
break ;
case 2 :
printf ( " Two " ) ;
break ;
case 3 :
printf ( " Three " ) ;
break ;
case 4 :
printf ( " Four " ) ;
break ;
case 5 :
printf ( " Five " ) ;
break ;
case 6 :
printf ( " Six " ) ;
break ;
case 7 :
printf ( " Seven " ) ;
break ;
case 8 :
printf ( " Eight " ) ;
break ;
case 9 :
printf ( " Nine " ) ;
break ;
}
num = num / 10 ;
}
return 0 ;
**
* C program to display number in word
* /
# include < stdio . h >
# include < math . h >
int main( )
{
int n , num = 0 , digits ;
/ * Input number from user * /
printf( " Enter any number to print
scanf( " % d " , & n ) ;
/ * Find total digits in n * /
digits = ( int ) log 10 ( n ) ;
/ * Store reverse of n in num * /
while( n != 0 )
{
num = ( num * 10 ) + ( n % 10 ) ;
n / = 10 ;
}
/ * Find total trailing zeros * /
digits = digits - ( ( int ) log 10 ( nu
/ *
* Extract last digit of number an
* till num becomes 0
* /
while( num != 0 )
{
switch ( num % 10 )
{
case 0 :
printf ( " Zero " ) ;
break ;
case 1 :
printf ( " One " ) ;
break ;
case 2 :
printf ( " Two " ) ;
break ;
case 3 :
printf ( " Three " ) ;
break ;
case 4 :
printf ( " Four " ) ;
break ;
case 5 :
printf ( " Five " ) ;
break ;
case 6 :
printf ( " Six " ) ;
break ;
case 7 :
printf ( " Seven " ) ;
break ;
case 8 :
printf ( " Eight " ) ;
break ;
case 9 :
printf ( " Nine " ) ;
break ;
}
num / = 10 ;
}
/ * Print all trailing zeros * /
while( digits )
{
printf ( " Zero " ) ;
digits - - ;
}
return 0 ;