write a program in c to calculate sum of prime numbers
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Answer:
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Explanation:
Program to find sum of prime numbers between 1 to n
/**
* C program to find sum of prime numbers between 1 to n
*/
#include <stdio.h>
int main()
{
int i, j, end, isPrime, sum=0;
/* Input upper limit from user */
printf("Find sum of all prime between 1 to : ");
scanf("%d", &end);
/* Find all prime numbers between 1 to end */
for(i=2; i<=end; i++)
{
/* Check if the current number i is Prime or not */
isPrime = 1;
for(j=2; j<=i/2 ;j++)
{
if(i%j==0)
{
/* 'i' is not prime */
isPrime = 0;
break;
}
}
/*
* If 'i' is Prime then add to sum
*/
if(isPrime==1)
{
sum += i;
}
}
printf("Sum of all prime numbers between 1 to %d = %d", end, sum);
return 0;
}
Program to find sum of prime numbers in given range
/**
* C program to find sum of prime numbers in given range
*/
#include <stdio.h>
int main()
{
int i, j, start, end;
int isPrime, sum=0;
/* Input lower and upper limit from user */
printf("Enter lower limit: ");
scanf("%d", &start);
printf("Enter upper limit: ");
scanf("%d", &end);
/* Find all prime numbers in given range */
for(i=start; i<=end; i++)
{
/* Check if the current number i is Prime or not */
isPrime = 1;
for(j=2; j<=i/2 ;j++)
{
if(i%j==0)
{
/* 'i' is not prime */
isPrime = 0;
break;
}
}
/*
* If i is Prime then add to sum
*/
if(isPrime==1)
{
sum += i;
}
}
printf("Sum of all prime numbers between %d to %d = %d", start, end, sum);
return 0;
}
Explanation:
Code for sum of prime numbers in c++
#include<iostream>
int main(){
int num,i,count,sum=0;
for(num = 1;num<=100;num++){
count = 0;
for(i=2;i<=num/2;i++){
if(num%i==0){
count++;
break;
}
}
if(count==0 && num!= 1)
sum = sum + num;
}
cout << "Sum of prime numbers is: " << sum;
return 0;
}
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