Question

Write a program in C using pointers to display the sum and average of numbers from m to n.

Answer 1

Answer:

Explanation :#include <stdio.h>

#include <conio.h>

void main()

{

int n,*p,sum=0,i;

float avg;

clrscr();

printf("\nHOW MANY NUMBERS: ");

scanf("%d",&n);

p=(int *) malloc(n*2);

if(p==NULL)

{

 printf("\nMEMORY ALLOCATION UNSUCCCESSFUL");

 exit();

}

for(i=0;i<n;i++)

{

 printf("\nENTER NUMBER %d: ",i+1);

 scanf("%d",(p+i));

}

for(i=0;i<n;i++)

 sum=sum+*(p+i);

avg=(float)sum/n;

printf("\nTHE AVERAGE OF THE NUMBERS IS %0.2f",avg);

getch();

}

Answer 2

Answer:

written below-

Explanation:

* C Program to to find the mean of n number using pointer *\

# include < stdio.h >

int main( )

{

int a[20], n, i, sum=0 ;

float mean ;

int *ptr ;

printf(" How many Numner you want to enter: ") ;

scanf("%d ",& n) ;

printf("\n Enter the number : \n") ;

for (i = 0; i < n ; i++ )

{

scanf("%d ",& a[i]) ;

ptr++ ;

}

ptr = & a[0] ;

printf(" \n Element in array are :\n ") ;

for (i = 0; i < n ; i++ )

{

printf("\t %d ",( *ptr )) ;

sum = sum + *ptr ;

ptr++ ;

}

mean = sum / n ;

printf("\n Mean of %d Numbers are : %f ",n, mean) ;

return ( 0 );

}

#SPJ2