Write a program in Java for the following :-
b) To input five subjects marks and print the total and
percentage using java.io
Answers
Answer:
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Explanation:
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Explanation:
This program calculates the grade of a student based on the marks entered by user in each subject. Program prints the grade based on this logic.
If the average of marks is >= 80 then prints Grade 'A'
If the average is <80 and >=60 then prints Grade 'B'
If the average is <60 and >=40 then prints
Grade 'C'
else prints Grade 'D'
To understand this Program you should have the knowledge of following concepts of Java:
Java For Loop
Arrays in Java
if..else-if in Java
Example: Program to display the grade of
student
import java.util.Scanner;
public class JavaExample
import java.util.Scanner;
public class JavaExample
{
public static void main(String args[])
{
/* This program assumes that the student has 6 subjects,
* thats why I have created the array of
size 6. You can
* change this as per the requirement.
*/
int marks[] = new int[6];
int i;
float total=0, avg;
Scanner scanner = new Scanner(System.in);
for(i=0; i<6; i++) {
System.out.print("Enter Marks of Subject"+(i+1)+":");
marks[i] = scanner.nextInt();
total = total + marks[i];
Scanner scanner = new Scanner(System.in);
for(i=0; i<6; i++) {
System.out.print("Enter Marks of Subject"+(i+1)+":");
marks[i] = scanner.nextInt();
total = total + marks[i];
}
scanner.close();
//Calculating average here
avg = total/6;
System.out.print("The student Grade is:
if(avg>=80)
{
}
System.out.print("A");
else if(avg>=60 && avg<80)
{
}
System.out.print("B");
else if(avg>=40 && avg<60)
{
{
}
C30 ال
System.out.print("B");
else if(avg>=40 && avg<60)
{
}
System.out.print("C");
else
{
}
System.out.print("D");
}
}
Output:
Enter Marks of Subject1:40
Enter Marks of Subject2:80
Enter Marks of Subject3:80
Enter Marks of Subject4:40
Enter Marks of Subject5:60
Enter Marks of Subject6:60
The student Grade is: B