Question

Write a program in Java to accept a number and check whether the number is a palindrome or not.​

Answer 1

Answer:

class PalindromeExample{  

public static void main(String args[]){  

 int r,sum=0,temp;    

 int n=454;//It is the number variable to be checked for palindrome  

 

 temp=n;    

 while(n>0){    

  r=n%10;  //getting remainder  

  sum=(sum*10)+r;    

  n=n/10;    

 }    

 if(temp==sum)    

  System.out.println("palindrome number ");    

 else    

  System.out.println("not palindrome");    

}  

}  

Explanation:

Palindrome number in java: A palindrome number is a number that is same after reverse. For example 545, 151, 34543, 343, 171, 48984 are the palindrome numbers. It can also be a string like LOL, MADAM etc.

Palindrome number algorithm

Get the number to check for palindrome

Hold the number in temporary variable

Reverse the number

Compare the temporary number with reversed number

If both numbers are same, print "palindrome number"

Else print "not palindrome number"

Answer 2

Provided solution to the question asked to check whether the number entered by the user in Java is palindrome or not.

Introduction or Explanation:

Palindrome can be defined as a word, a number or sentence that reads the same backwards.

For Example:

• String:-

• RACECAR
• KANAK
• JALAJ
• LOL, etc.

• Number:-

• 32166123
• 45754
• 9822289
• 61316, etc.

Program:

import java.util.*;

class Palindrome

{

public static void main(String args[])

{

Scanner in = new Scanner(System.in);

int n, int r = 0;

System.out.println("Enter the number: ");

int num = in.nextInt();

while(n != 0)

{

int dig = n % 10;

n /= 10;

r = r * 10 + dig;

}

if (r == num)

System.out.println("A Palindrome number");

else

System.out.println("Not a Palindrome number");

}

}