Write a program in Java to accept a number and display its factors?
Answers
Your answer is here dear....
Explanation:
public class Factors {
public static void main(String[] args) {
int number = 60;
System.out.print("Factors of " + number + " are: ");
for(int i = 1; i <= number; ++i) {
if (number % i == 0) {
System.out.print(i + " ");
}
}
}
}
When you run the program, the output will be:
Factors of 60 are: 1 2 3 4 5 6 10 12 15 20 30 60
In the above program, number whosefactors are to be found is stored in the variable number (60).
The for loop is iterated until i <= number is false. In each iteration, whether number is exactly divisible by i is checked (condition for i to be the factor of number) and the value of i is incremented by 1.
HOPE. It's HELP YOU DEAR....
Answer:
input the no. using while loop
