Computer Science, asked by monosijdas82pa9gm5, 9 months ago

Write a program in java to accept an integer array with n number of elements. Reverse each elements of the array. Display the original array ,array after reversing each element in the original order and in the reverse order.

Answers

Answered by nishapragu
0

Explanation:

Reversing an array in java can be done in three simple methods.

Reversing an array in java can be done in three simple methods.Examples:

Reversing an array in java can be done in three simple methods.Examples:Input : 1, 2, 3, 4, 5

Reversing an array in java can be done in three simple methods.Examples:Input : 1, 2, 3, 4, 5Output :5, 4, 3, 2, 1

Reversing an array in java can be done in three simple methods.Examples:Input : 1, 2, 3, 4, 5Output :5, 4, 3, 2, 1Input : 10, 20, 30, 40

Reversing an array in java can be done in three simple methods.Examples:Input : 1, 2, 3, 4, 5Output :5, 4, 3, 2, 1Input : 10, 20, 30, 40Output : 40, 30, 20, 10

Reversing an array in java can be done in three simple methods.Examples:Input : 1, 2, 3, 4, 5Output :5, 4, 3, 2, 1Input : 10, 20, 30, 40Output : 40, 30, 20, 10The first method is as follows:

Reversing an array in java can be done in three simple methods.Examples:Input : 1, 2, 3, 4, 5Output :5, 4, 3, 2, 1Input : 10, 20, 30, 40Output : 40, 30, 20, 10The first method is as follows:(i) Take input the size of array and the elements of array.

Reversing an array in java can be done in three simple methods.Examples:Input : 1, 2, 3, 4, 5Output :5, 4, 3, 2, 1Input : 10, 20, 30, 40Output : 40, 30, 20, 10The first method is as follows:(i) Take input the size of array and the elements of array.(ii) Consider a function reverse which takes the parameters-the array(say arr) and the size of the array(say n).

Reversing an array in java can be done in three simple methods.Examples:Input : 1, 2, 3, 4, 5Output :5, 4, 3, 2, 1Input : 10, 20, 30, 40Output : 40, 30, 20, 10The first method is as follows:(i) Take input the size of array and the elements of array.(ii) Consider a function reverse which takes the parameters-the array(say arr) and the size of the array(say n).(iii) Inside the function, a new array (with the array size of the first array, arr) is initialized. The array arr[] is iterated from the first element and each element of array arr[] is placed in the new array from the back, i.e, the new array is iterated from its last element.

Reversing an array in java can be done in three simple methods.Examples:Input : 1, 2, 3, 4, 5Output :5, 4, 3, 2, 1Input : 10, 20, 30, 40Output : 40, 30, 20, 10The first method is as follows:(i) Take input the size of array and the elements of array.(ii) Consider a function reverse which takes the parameters-the array(say arr) and the size of the array(say n).(iii) Inside the function, a new array (with the array size of the first array, arr) is initialized. The array arr[] is iterated from the first element and each element of array arr[] is placed in the new array from the back, i.e, the new array is iterated from its last element.(iv) In this way, all the elements of the array arr[] are placed reversely in the new array.

Reversing an array in java can be done in three simple methods.Examples:Input : 1, 2, 3, 4, 5Output :5, 4, 3, 2, 1Input : 10, 20, 30, 40Output : 40, 30, 20, 10The first method is as follows:(i) Take input the size of array and the elements of array.(ii) Consider a function reverse which takes the parameters-the array(say arr) and the size of the array(say n).(iii) Inside the function, a new array (with the array size of the first array, arr) is initialized. The array arr[] is iterated from the first element and each element of array arr[] is placed in the new array from the back, i.e, the new array is iterated from its last element.(iv) In this way, all the elements of the array arr[] are placed reversely in the new array.(v) Further, we can iterate through the new array from the beginning and print the elements of the array.

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Answered by mpd20700
0

Answer:

import java.util.*;

class Reverse

{

   public static void main(String[]args)

   {

       Scanner sc=new Scanner(System.in);

       System.out.println("Enter the value of n");

       int n=sc.nextInt();

       int original[]=new int[n];

       System.out.println("Enter "+n+" integers");

       for(int i=0;i<n;i++)

       {

           original[i]=sc.nextInt();

       }

       int reverse[]=new int[n];

       for(int j=0;j<original.length;j++)

       {

           int temp=original[j];

           int rev=0;

           while(original[j]!=0)

           {

               int digit=temp%10;

               rev=(rev*10)+digit;

               temp=temp/10;

           }

           reverse[j]=rev;

       }

       System.out.println("Original array");

       for(int k=0;k<original.length;k++)

       {

           System.out.println(original[k]);

       }

       System.out.println("Final array");

       for(int l=0;l<original.length;l++)

       {

           System.out.println(reverse[l]);

       }

   }

}

   

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