Write a program in JAVA to check whether a series belongs to PseudoArithmetic sequence.
The logic is :
Sequence of n integers : 2, 5, 6, 8, 9, 12 We observe that 2 + 12 = 5 + 9 = 6 +8 = 14
The sum of the above sequence can be calculated as 14 x 3 = 42
For sequence containing an odd number of elements the rule is to double the middle element, for example 2, 5, 7, 9, 12
=2 +12 = 5 +9 = 7 +7 = 14
14 x 3 = 42 [ middle element = 7]
schoolstudent:
pseudo arithmetic sequence is a series of integers in an order where the sum of the pairs of elements at equidistance from front and end remain same.
would sequence is user defined.. or the same one..
sequence is user defined
now you give correct definition...
can no one answer this question??
hey i am answer always but program and logic took some time too think.
Answers
Answered by
12
import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
int []a=new int[n];
System.out.println("enter the sequence values");
for(int i=0;i<n;i++){
a[i]=sc.nextInt();
}
int sum=a[0]+a[(a.length-1)];
if(n%2==0){
int c=0;
for(int i=0;i<n/2;i++){
int temp_sum=a[i]+a[(a.length-1)-i];
if(temp_sum==sum)
continue;
else{
System.out.println("not a pesudo arithemitic sequence");
c++;
}
break;
}
if(c==0)
System.out.println("sum of pesudo arithmetic number is:" +(sum*(n/2)));
}
else{
int c=0;
for(int i=0;i<n/2;i++){
int temp_sum1;
if(i!=(n/2)+1){
temp_sum1=a[i]+a[(a.length-1)-i];}
else{
a[(a.length-1)-i]=a[i];
temp_sum1=a[i]+a[(a.length-1)-i];
}
if(temp_sum1==sum)
continue;
else{
System.out.println("not a pesudo arithemitic sequence");
c++;
}
break;
}
if(c==0)
System.out.println("sum of pesudo arithmetic number is:" +(sum*((n/2)+1)));
}
}
}
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0
what is the output of this program
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