Question

write a program in java to display all odd numbers from 1 to 20 by using continue statement in while loop
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Answer 1

Required Answer:-

Question:

• Write a Java program to display all odd numbers from 1 to 20 using continue statement.

Solution:

Here is the code.

1. public class JavaBrainly {
2. public static void main(String[] args) {
3. for(int i=1;i<=20;i++)
4. {
5. if(i%2==0)
6. continue;
7. System.out.print(i+" ");
8. }
9. }
10. }

Explanation:

• We are asked to print all the odd numbers from 1 to 20 using continue statement. The continue statement breaks the current iteration and moves to the next iteration. So, if a number is even, the continue statements moves to the next iteration without printing the value.

Answer 2

Answer:

you have different explanations on different languages here is the some.

C LANGUAGE:

#include<stdio.h>

int main()

{

int i;

for(i=0;i<=20;i+=2)printf(“%d\n”,i);

for(i=1;i<=20;i+=2)printf(“%d\n”,i);

return 0;

}

CPP:

#include<iostream.h>

using namespace std;

int main(){

int i;

for(i=0;i<=20;i+=2)cout<<i<<endl;

for(i=1;i<=20;i+=2)cout<<i<<endl;

return 0;

}

PYTHON:

print “this is a even number list”

even_list=[]

odd_list=[]

for i in Xrange(20):

if i%2==0:

print i

even_list.append(i)

print “this is a odd number list”;

for i in Xrange(20):

if i not in even_list:

odd_list.append(i)

print odd_list

logic behind each section is same and is simple.