Question

Write a program in JAVA to enter a number and check and print whether the number is Armstrong or not.

★ A number is said to be Armstrong, if the sum of the cubes of the digits is equal to the original number.​

Answer 1

Answer:-

★ Program to check for Armstrong number in Java:-

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$\pink{\bigstar}$ $\large\underline{\underline{\bf\green{C{o}de:-}}}$

import java.util.*;

public class Armstrong

{

public static void main(String args[])

{

Scanner in = new Scanner (System.in);

int n,num,a,s=0;

System.out.println("Enter a Number:");

n=in.nextInt();

num=n;

while(n>0)

{

a=n%10;

s=s+a*a*a;

n=n/10;

}

if(num==s)

System.out.println("It is an Armstrong Number");

else

System.out.println("It is NOT an Armstrong Number");

}

}

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$\pink{\bigstar}$ $\large\underline{\underline{\bf\green{Out{p}ut:-}}}$

★ Refer to the attachment for Output.

★ Input value in the above Output is 153.

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$\red{\bigstar}$ Explore More:-

✯ Here, is the list of all 3 digit Armstrong numbers.

• 153

• 370

• 371

• 407

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✯ In 4 digit Armstrong numbers like 1634, 8208 and 9474 the sum of the power of four of the digits is equal to the original number.

Answer 2

Answer:

//Java Program to check if a number is Armstrong number or not.

import java.util.*;

public class Armstrong {

public static void main(String[] args) {

Scanner sc=new Scanner (System.in);

long n=sc.nextInt(); //Enter a number

int c=0,s=0;long n1=n;

while (n!=0)

{

c++;

n/=10;

}

n=n1;

while (n1!=0)

{

s+=Math.pow(n1%10,c);

n1/=10;

}

if(s==n)

System.out.println("Armstrong");

}

}

Variable Description:-

• n:- to Accept input
• c:- counter variable
• s:- sum variable
• n1:- to make the copy of the original number.

• Output Attached.