write a program in Java to find the area and perimeter of rectangle by using assignment operator
Answers
Answered by
46
//To find the area,perimeter of a rectangle
public class Rectangle
{
public static void main(String args[])
{
int 1,b,ar,p;
double d;
1=24;b=10;
ar=1*b;
p=2*(1+b);
d=Math.sqrt(1*1+b*b);
System.out.println("The area of rectangle="+ar);
System.out.println("The perimeter of rectangle="+p);
}
}
public class Rectangle
{
public static void main(String args[])
{
int 1,b,ar,p;
double d;
1=24;b=10;
ar=1*b;
p=2*(1+b);
d=Math.sqrt(1*1+b*b);
System.out.println("The area of rectangle="+ar);
System.out.println("The perimeter of rectangle="+p);
}
}
Answered by
8
public static void main(String[] args)
{
int l, b, perimeter, area;
Scanner s = new Scanner(System.in);
System.out.print("Enter length of rectangle:");
l = s.nextInt();
System.out.print("Enter breadth of rectangle:");
b = s.nextInt();
perimeter = 2 * (l + b);
System.out.println("Perimeter of rectangle:"+perimeter);
area = l * b;
System.out.println("Area of rectangle:"+area);
}
}
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