Question

Write a program in java to find the sum of the given series: i) S = 1+1+2+3+5+....................to n terms ii) S = 2-4+6-8+...........................to n iii) S = a - a^3/5 + a^5 /9 – a^7 /13 .......................to n terms

Answer 1

Question 1:-

WAP in Java to find the sum of the given series.

1+2+3+4+5+.....N terms.

Code:-

import java.util.*;

class Series1

{

public static void main(String str[])

{

Scanner sc = new Scanner(System.in);

System.out.print("Enter the number of terms for the series: ");

int n=sc.nextInt();

int s=0;

for(int i=1;i<=n;i++)

s+=i;

System.out.println("Sum of the series: "+s);

}

}

Question 2:-

WAP in Java to find the sum of the series.

2-4+6-8+10-12+.......N

Code:-

import java.util.*;

class Series2

{

public static void main(String args[])

{

Scanner sc=new Scanner(System.in);

System.out.print("Enter the number of terms for the series: ");

int n=sc.nextInt();

int s=0;

int a=1, b=2;

for(int i=1;i<=n;i++)

{

s=s+(b*a);

a*=-1;

b+=2;

}

System.out.println("Sum of the series is: "+s);

}

}

Question 3:-

WAP in Java to find the sum of the series.

$\sf S = a - \frac{ {a}^{3} }{5} + \frac{ {a}^{5} }{9} - .....$

Code:-

import java.util.*;

class Series3

{

public static void main(String args[])

{

Scanner sc = new Scanner(System.in);

System.out.print("Enter the value of a: ");

double a=sc.nextDouble();

System.out.print("Enter the value of n: ");

int n=sc.nextInt();

double s=0.0;

double x=1.0;

int b=1;

for(int i=1;i<=n;i++,b+=2,x+=4)

{

s=s+(Math.pow(-1,i+1)*Math.pow(a,b))/x;

}

System.out.println("Sum of the series is: "+s);

}

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