Write a program in java to read and store 10 numbers in an array and add 2 to the even numbers and 3 to all odd numbers and then display the array.
Answers
Answer:
class BubbleSortExample {
public static void main(String []args) {
int num, i, j, temp;
Scanner input = new Scanner(System.in);
System.out.println("Enter the number of integers to sort:");
num = input.nextInt();
int array[] = new int[num];
System.out.println("Enter " + num + " integers: ");
for (i = 0; i < num; i++)
array[i] = input.nextInt();
for (i = 0; i < ( num - 1 ); i++) {
for (j = 0; j < num - i - 1; j++) {
if (array[j] > array[j+1])
{
temp = array[j];
array[j] = array[j+1];
array[j+1] = temp;
}
}
}
System.out.println("Sorted list of integers:");
for (i = 0; i < num; i++)
System.out.println(array[i]);
}
}
Output:
Enter the number of integers to sort:
6
Enter 6 integers:
12
6
78
9
45
08
Sorted list of integers:
6
8
9
12
45
78
Bubble sort program for sorting in descending Order
In order to sort in descending order we just need to change the logic array[j] > array[j+1] to array[j] < array[j+1] in the above program. Complete code as follows:
import java.util.Scanner;
class BubbleSortExample {
public static void main(String []args) {
int num, i, j, temp;
Scanner input = new Scanner(System.in);
System.out.println("Enter the number of integers to sort:");
num = input.nextInt();
int array[] = new int[num];
System.out.println("Enter " + num + " integers: ");
for (i = 0; i < num; i++)
array[i] = input.nextInt();
for (i = 0; i < ( num - 1 ); i++) {
for (j = 0; j < num - i - 1; j++) {
if (array[j] < array[j+1])
{
temp = array[j];
array[j] = array[j+1];
array[j+1] = temp;
}
}
}
System.out.println("Sorted list of integers:");
for (i = 0; i < num; i++)
System.out.println(array[i]);
Explanation: