Write a program in PHP to check whether the person is adult Orr not
Answers
Answered by
0
Answer:
Here
Explanation:
<?
if(person<=18){
echo "You are not adult"
}else{
echo"You are adult"
}
Answered by
0
Below are the program in php for the above problem:
Explanation:
<?php
$personage=88;// Initialize a variable with a value, the value can also take by the help of HTML form.
if($personage>18) //check the if condition for age is greater than 18 or not.
echo "A person is an adult person"; //print for adult.
else
echo"The person is not an adult person"; //print if a person is not adult.
?>
Output:
- The above code output that "A person is an adult person".
- But when the value of personage variable will be changed to 18, then it will prints that "The person is not an adult person".
Code Explanation:
- The above code is in the PHP language. There is a variable that takes static value.
- But this program will work for a different dynamic value.
- The value can be inserted by the HTML code.
- Then the program checks that the age is an adult age or not with the help of if-else statement.
Learn more:
- PHP : https://brainly.in/question/5829839
Similar questions
Hindi,
5 months ago
Political Science,
11 months ago